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Find the zero of the polynomial in each of the following cases

(I) P(x) = x + 5
(II) P(x) = x - 5
(III) P(x) = 2x + 5​

User XardasLord
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7.4k points

1 Answer

4 votes

Answer:

(I) (-5) is a zero of P(x)

(II) 5 is a zero of P(x)

(III) (-5/2) is a zero of P(x)

Explanation:

(I) P(x) = x + 5

Here, P(x) = x + 5

To find the zeroes of P(x)

let P(x) = 0

∴ x + 5 = 0

x = (-5)

Thus, (-5) is a zero of P(x)

(II) P(x) = x - 5

Here, P(x) = x - 5

To find the zeroes of P(x)

let P(x) = 0

∴ x - 5 = 0

x = 5

Thus, 5 is a zero of P(x)

(III) P(x) = 2x + 5

Here, P(x) = 2x + 5

To find the zeroes of P(x)

let P(x) = 0

∴ 2x + 5 = 0

∴ 2x = -5

x = (-5/2)

Thus, (-5/2) is a zero of P(x)

-TheUnknownScientist

User Ti Strga
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8.9k points

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