Question

asked Jan 27, 2023 199k views

1 Answer

Cannon · Answer 1 · 2023-02-01T02:49:35+0000

Solve for x

2x - 5y = 1

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term -5y to the other side of equation.

$\rm{2x - 5y = 1 }\\$

$\rm{2x - 5y + 5y = 1 + 5y}\\$

Subtract -5y from both sides of the equation

Simplify 2x - 5y + 5y = 1 + 5y

Cancel -5y with 5y

Reorder 1 + 5y so highest order terms are first

$\rm{x = (5y + 1)/(2) } \\$

Move factors not having X from the left side of equation 2x = 5y + 1

$\rm{ (2x)/(2) = (5y + 1)/(2) } \\$

Divide both sides of equation 2x = 5y + 1 by 2

Cancel 2 with 2

$\rm{ \frac{\cancel{2}x}{\cancel{2}} = (5y + 1)/(2) } \\$

$\rm{x = (5y + 1)/(2) } \\$

Therefore, the x of 2x - 5y = 1 is
$\rm{ (5y + 1)/(2) }$

Solve for y

2x - 5y = 1

$\rm{-5y + 2x = 1}\\$

Reorder 2x -5y so highest order terms are first

-5y = -2x + 1

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2x to the other side of equation -5y + 2x = 1

$\rm{-5y + 2x - 2x = 1 - 2x}\\$

Subtract 2x from both sides of the equation

Simply - 5y + 2x -2x = 1 - 2x

Cancel 2x with -2x

Reorder 1 - 2x so highest order terms are first

$\rm{y = - (2x + 1)/(5) }\\$

Move factors not having y from the left side of equation -5y = -2x + 1

$\rm{ ( - 5y)/( - 5) = ( - 2x + 1)/( - 5) }\\$

Divide both sides of equation -5y = -2x +1 by -5

Simplify
$\rm{ ( - 5y)/( - 5) = ( - 2x + 1)/( - 5) }$

Cancel 5 with -5

Resolve sign on fraction
$\rm{( - 2x + 1)/( - 5) }$

Therefore, the y of 2x-5y = 1 is
$\rm{( - 2x + 1)/( - 5) }$

Solve for x

3x + 2y = 11

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 3 x + 2y - 2y = 11 - 2y

Subtract 2y from the both sides of the equation

Simplify 3x + 2y - 2y = 11 - 2y

Cancel 2y with 2y

Reorder 11 - 2y so highest order terms are first

$\rm{x = (2y + 11)/(3) } \\$

Move the factors not having x from the left side of equation 3x = -2y +11

$\rm{ (3x)/(3) = (-2y + 11)/(3) } \\$

Divide both sides of equation 3x = 2y + 11 by 3

Cancel 3 with 3

$\rm{ \frac{\cancel{3}x}{\cancel{3}} = (-2y + 11)/(3) } \\$

$\rm{x = (2y + 11)/(3) } \\$

Therefore, the x for 3x + 2y = 11 is
$\rm{ (2y + 11)/(3) }$

Solve for y

2y + 3x = 11

Reorder 3x + 2y so highest order terms are first

$\rm{2y + 3x = 11}\\$

We need to group all the variable terms on one side and all the constant terms on the other side of the equation. Therefore move the term 2:y to the other side of equation 2y + 3x = 11

$\rm{2y + 3x - 3x = 11 - 3x}$