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What method would you use to square the value 3 + √-1 ? In what other cases would you use this method? Explain.

1 Answer

3 votes

Answer:

1) the types of number are the negative integers (e.g √-1 √-3 √-5 are not defined)

2) the answer is No, proof: 2x√-1 is not defined because √-1 doesn't exist

3) the answer is No, proof: √-1 - 3 is not defined because √-1 doesn't exist

4) the answer is Yes, proof: (√-1 )²= -1 this is a real number

5) the answer is No, proof: (√-1 )^3= (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist

6) the result would be defined with the following cases:

√-1+n, n>1

√-1xn, n<0

√-1/n, n<0

7) the result would not be defined with the following cases:

√-1+n, n<0

√-1xn, n>0

√-1/n, n>0

8) to square 3 + √-1, I use the method of complex number

i²= -1, it implies i= √-1

so 3+√-1=3+i, and then (3+√-1)²=(3+i)²= 9 -1+6i= 8-i= 8-√-1

9) it is used for finding complex roots of a number

Explanation: