Question

I need help with this!

Answer 1

If
`3x-y=12`, then
`y=3x-12`. Substituting that into
`(8^x)/(2^y)` would give us...

`\begin{aligned}(8^x)/(2^y) &= (8^x)/(2^(3x-12)) \\[0.9em]&= (8^x)/(2^(3x)\cdot2^(-12))\\[0.9em]&= (8^x)/((2^3)^x\cdot2^(-12))\\[0.9em]&= (8^x)/(8^(x)\cdot2^(-12))\\[0.9em]&= (1)/(1\cdot2^(-12))\\[0.9em]&= (1)/(2^(-12))\\[0.9em]&= 2^(12)\end{aligned}`