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The equation for line A is y= 1/3x+4. Suppose line A is parallel to line B and point (-3,1) lies on line B Y= -3x-8 Y=1/3x Y=-3x+4 Y=1/3x+2
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The equation for line A is y= 1/3x+4. Suppose line A is parallel to line B and point (-3,1) lies on line B

Y= -3x-8
Y=1/3x
Y=-3x+4
Y=1/3x+2

User David Fraser
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1 Answer

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Parallel lines have same slope
y = 1/3x + 4, the slope is 1/3
Therefore y = 1/3x + b
Plug in the point (-3,1)
1 = 1/3(-3) + b
1 = -1 + b, b = 2
Solution: y = 1/3x + 2
User Andreycpp
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8.0k points
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