Question

Math is hard PLS HELP

Answer 1

B

Explanation:

y=|x-3|

y=1/2 x

|x-3|=1/2x

if |x|=a

x=±a

x-3=±1/2 x

when x-3=1/2x

2x-6=x

x=6

so y=6/2=3

point is (6,3)

when x-3=-1/2 x

2x-6=-x

3x=6

x=6/3=2

y=1/2 x=1/2×2=1

point is (2,1)

distance=√[(2-6)²+(1-3)²]=√[16+4]=√20