Question

Five resistors, each 10 Ω, are connected in parallel to a voltage source.

What is the equivalent resistance of the circuit?

Group of answer choices

20 Ω

5 Ω

2 Ω

50 Ω

Flag question: Question 3
Question 35 pts
Five resistors, each 10 Ω, are connected in parallel to a voltage source.

The current at each branch is measured to be 600 mA. What is the potential difference supplied by the voltage source?

Group of answer choices

12 V

6 V

0.3 V

3 V

Flag question: Question 4
Question 45 pts
A 2.5 kΩ resistor and a 20.0 Ω resistor are connected to a 9.0 V source in parallel. What is the total current in the circuit?
Group of answer choices

3.6 mA

450 mA

20 A

180 A

Answer 1

The equivalent resistance of the circuit is 2 Ω. The potential difference supplied by the voltage source is 1.2 V. Since the current at each branch is 600 mA, which is equal to 0.6 A, and the equivalent resistance of the circuit is 2 Ω, the potential difference supplied by the voltage source can be calculated as V = (0.6 A) * (2 Ω) = 1.2 V.

Step-by-step explanation:

In a parallel circuit, the equivalent resistance is calculated by taking the reciprocal of the sum of the reciprocals of the individual resistances.

In this case, since all five resistors are 10 Ω each, the total resistance is 2 Ω.

So, the equivalent resistance of the circuit is 2 Ω.

The potential difference supplied by the voltage source can be calculated using Ohm's Law, which states that V = IR, where V is the potential difference, I is the current, and R is the resistance.

Since the current at each branch is 600 mA, which is equal to 0.6 A, and the equivalent resistance of the circuit is 2 Ω, the potential difference supplied by the voltage source can be calculated as V = (0.6 A) * (2 Ω) = 1.2 V.