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PLease help me with this!

1. x2 - 9 > 0

2. x2 - 8x + 12 > 0

3. -x2 - 12x - 32 > 0

4. x2 + 3x - 20 >= 3x + 5

1 Answer

4 votes

Answer:

1. x2 - 9 > 0

x^2-3^2>0

(x+3)(x-3)>0

(x+3)>0 and (x-3)>0

x>-3 and x>3

2. x2 - 8x + 12 > 0

x^2 - 8x +12>0

x^2 -2x -6x +12 >0 (-8x is replaced by (-2x) + (-6x) )

x(x-2) -6(x-2) >0

(x-6)(x-2)>0

(x-6)>0 and (x-2)>0

x>6 and x>2

3. -x2 - 12x - 32 > 0

-x^2 -12x -32 >0

x^2 +12x +32 <0

x^2 +4x +8x +32<0

x(x+4) +8(x+4)<0

(x+8)(x+4)<0

(x+8)<0 and (x+4)<0

x<-8 and x<-4

4. x2 + 3x - 20 >= 3x + 5

x^2 +3x -20 >= 3x +5

x^2 +3x -20 -3x >= 3x +5 -3x

x^2 -20 >= 5

x^2 -20 +20 >= 5 +20

x^2 >=25

x^2-25 >=0

(x-5)(x+5)>=0

(x-5)>=0 and (x+5)>=0

x>=5 and x>=-5

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