Answer:
1/5³ = 1/125 = 5⁻³
Explanation:
It can be useful to remember that an exponent signifies repeated multiplication.
5^3 = 5×5×5
5^6 = 5×5×5×5×5×5
Then the ratio is ...
![(5^3)/(5^6)=(5*5*5)/(5*5*5*5*5*5)=(1)/(5*5*5)=\boxed{(1)/(125)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/gkhnsrm1zlprjzc6ziwqxu159iqxlbbc2e.png)
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If you want to leave this in terms of exponents, you can see that factors in the denominator cancel (subtract from) those in the numerator. That is ...
![(5^3)/(5^6)=(5^(3-3))/(5^(6-3))=(5^0)/(5^3)=\boxed{(1)/(5^3)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/v5d3opp68t1jnv6vkz38kcl495ue3j8bpl.png)
The same sort of exponent arithmetic works to leave a numerator value with a negative exponent:
![(5^3)/(5^6)=(5^(3-6))/(5^(6-6))=(5^(-3))/(5^0)=(5^(-3))/(1)=\boxed{5^(-3)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/d9ydxya9ivt1ci3g17y4h4ldsn62yaxl4n.png)
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Additional comment
These ideas are formulated as the rules of exponents:
- (a^b)/(a^c) = a^(b-c)
- 1/(a^b) = a^-b