Question

An arrow is shot vertically downwards, and strikes the ground at a speed of 29.2 m/s, 10.9 m below from where it was shot. With what initial speed was the arrow shot?

Answer 1

Step-by-step explanation:

Ignoring air resistance

v² = u² + 2as

u = √(v² - 2as)

u = √(29.2² - 2(9.81)(10.9))

u = 25.27413... 25.3 m/s