Question

Let f(x)=4x^2-2
f(t+1)

Answer 1

`f(x) = 4 {x}^(2) - 2 \\ f(t + 1) = 4 {(t + 1)}^(2) - 2 \\ = 4( t + 1)(t + 1) - 2 \\ = 4( {t}^(2) + 2t + 1) - 2 \\ = 4 {t}^(2) + 8t + 4 - 2 \\ = 4 {t}^(2) + 8t + 2`

I hope I helped you^_^