Question

What is the distance between the points P(-5, 4), Q(7, -5)

Answer 1

15

Explanation:

Distance between two points is = √(x2 - x1)² + (y2 - y1)²

x1 = -5, y1 = 4; x2 = 7, y2 = -5

|PQ| = √(7 - (-5))² + (-5 - 4)²

|PQ| = √(7 + 5)² + (-9)²

|PQ| = √(12)² + 81

|PQ| = √144 + 81

|PQ| = √225

|PQ| = 15