Question

A ladder 13 m long when set against the wall of house just reaches a window at a height of 12 m from the ground. How far is the lower end of the ladder from the base of the wall?

Answer 1

Let the ladder be AB=13m

Let the vertical height reached be AC=12m

Let the distance between the foot of the ladder and wall be BC= x meters

By Pythagoras Theorem,

(AB)^2=(AC)^2+(BC)^2

(13)^2=(12)^2+(x)^2

x^2=169-144

x^2=25

x = 5 meters

Therefore,the foot of the ladder is 5 m away from the wall.

Explanation:

Hope this helps!!!

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