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Given an arithmetic progression 230, 226, 222, ... determine the smallest value of n such that the nth term is smaller than 40. Hence, determine the nth term. [3 marks]
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40 votes
40 votes
Given an arithmetic progression 230, 226, 222, ... determine the smallest value of

n such that the nth term is smaller than 40. Hence, determine the nth term.
[3 marks]

User Akshay I
by
2.7k points

1 Answer

16 votes
16 votes

Answer:

Explanation:

226-230= (-4)

226-(-4)

=226+4

=230

tn= -4n+234

User Mago
by
2.4k points
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