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Matter is in a Liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of -38.17°C and a boiling point of 350 37°C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state?

(Hint: C= 5/9(F-32)) Express the range as an inequality

Let x represent the temperature in degrees Fahrenheit. What is the range of temperatures for which this substance is not in a liquid state?

(Type an inequality or a compound inequality. Simplify your answer. Use integers or decimals for any numbers in the expression. Round to three decimal places as needed.)​

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Final answer:

The range of temperatures for which the substance is not in a liquid state is F < -36.706 or F > 662.666.

Step-by-step explanation:

The range of temperatures in which the substance is not in a liquid state can be found by identifying the temperatures outside the melting and boiling points. The melting point is -38.17°C and the boiling point is 350.37°C. We can convert these temperatures to Fahrenheit using the formula C = 5/9(F-32). For the melting point, we have -38.17 = 5/9(F-32). Solving for F, we get F ≈ -36.706°F. For the boiling point, we have 350.37 = 5/9(-32). Solving for F, we get F ≈ 662.666°F. Therefore, the range of temperatures for which this substance is not in a liquid state is F < -36.706 or F > 662.666.

User Andrii Chertok
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