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2x^3-4xy(x+y^2) = 7y y+ 25xy = 0

2x^3-4xy(x+y^2) = 7y y+ 25xy = 0
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2x^3-4xy(x+y^2) = 7y
y+ 25xy = 0

User Yamen Ajjour
by
8.2k points

1 Answer

2 votes

Answer:

Answer

Explanation:

2x^3-4xy(x+y^2) = 7y

y+ 25xy = 0

User Marzi Heidari
by
7.7k points
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