Question

A tank containing 500 litres of water has a leak.if one-third of the water in the tank leaked out on monday and one-seventh of the remaining water in the tank leaked out on tuesday, how much water is left in the tank?​

Answer 1

Answer: 285.7L

Explanation:

Tank initially had 500L of water.

On Monday a third leaked out, therefore:

Amount of water that leaked = 500L x 1/3 = 166.6667 = 166.7L

Remaining water after Monday leak = 500-166.7 = 333.3333 = 333.3L

On Tuesday a seventh of the remaining water (333.3L) leaked out, therefore:

Amount of water that leaked: (333.3333) x 1/7 = 47.6190 =47.6L

Water left after both leaks =500L - (166.6667 + 47.6190)L = 500L - 214.2857L = 285.7143L = 285.7L.

OR Water left = 333.3333L - 47.6190L = 285.7143L = 285.7L