Question

Consider the line y = -2/3+1.

Find the equation of the line that is parallel to this line and passes through the point (9, -6).
Find the equation of the line that is perpendicular to this line and passes through the point (9, -6).

Answer 1

y = -2x/3 + 5

Explanation:

Formula

= y - y1 = m(x - x1)

from the question our

X1 = 9

y1 = -6

placing in equation

y - 9= -2/3( x - (-6) )

Note: m = gradient (-2/3)

3y -27 = -2x -12

3y = -2x -12 + 27

y = -2x/3 +15/3

y= -2x/3 +5