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If the inital pressure of an ideal gas at a temperature of 344 K is 0.917 atm, what is the pressure of the gas at 322 K?

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Answer: P2 = 0.858 atm

Step-by-step explanation:

Use the combined gas law: P1V1/T1 = P2V2/T2,

where the subscripts are the initial (1) and final (2) states. Temperature must be in Kelvin. We want P2, so rearrange the equation to solve for P2:

P2 = P1(V1/V2)(T2/T1)

Note how I've arranged the volume and temperature values: as ratios. Now it is easy to cancel units and see what is going to happen to the pressure if we lower the temperature. Since the pressure change is a function of (T2/T1), and we are lowering the temperature (T2), we'd expect this to decrease the pressure.

No information is given on volume, so we'll assume a convenient value of 1 liter. Now enter the data:

P2 = (0.917atm)*(1)*(322K/344K)

P2 = 0.858 atm

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