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\begin{gathered} \rm Prove \: that :- \\ { { \rm { f ( x ) = f ( 0 ) + (x)/(1!) f'(0) + (x²)/(2!) f''(0) + (x³)/(3!) f'''(0) + \cdot \cdot \cdot \cdot \cdot \cdot \cdot }}}\end{gathered}



User Etliens
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1 Answer

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The series you had provided is generally the Maclaurin's series , and we want to prove the series , this series is very very much useful in calculus , especially when you have to substitute a function by it's series . So now let's start !

Consider the function f(x) as series of a polynomials of nth (n ≥ 1) degree as


{\boxed{\bf{f(x)=a_(0)+a_(1)x+a_(2)x^(2)+a_(3)x^(3)+a_(4)x^(4)+\cdots \cdots \infty}}}

Now , at x = 0


{:\implies \quad \sf f(0)=a_(0)+a_(1)(0)+a_(2)(0)^(2)+a_(3)(0)^(3)+a_(4)(0)^(4)+\cdots \cdots \infty}


{\boxed{:\implies \quad \sf f(0)=a_(0)}}

Now , again consider the function that we assumed


{:\implies \quad \sf f(x)=a_(0)+a_(1)x+a_(2)x^(2)+a_(3)x^(3)+a_(4)x^(4)+\cdots \cdots \infty}

Differentiating both sides w.r.t.x will yield


{:\implies \quad \sf f^(\prime)(x)=0+a_(1)* 1+a_(2)* 2* x+a_(3)* 3* x^(2)+a_(4)* 4* x^(3)+\cdots \cdots \infty}


{:\implies \quad \sf f^(\prime)(x)=a_(1)+2a_(2)x+3a_(3)x^(2)+4a_(4)x^(3)\cdots \cdots \infty}

Now , put x = 0 ;


{:\implies \quad \sf f^(\prime)(0)=a_(1)+2a_(2)(0)+3a_(3)(0)^(2)+4a_(4)(0)^(3)\cdots \cdots \infty}


{:\implies \quad \sf f^(\prime)(0)=a_(1)}


{\boxed{:\implies \quad \sf a_(1)=(f^(\prime)(0))/(1!)}}

Now , consider ;


{:\implies \quad \sf f^(\prime)(x)=a_(1)+2a_(2)x+3a_(3)x^(2)+4a_(4)x^(3)\cdots \cdots \infty}

Differentiating both sides w.r.t.x now ;


{:\implies \quad \sf f^(\prime \prime)(x)=0+2* a_(2)* 1+3* a_(3)* 2* x+4* a_(4)* 3* x^(2)\cdots \cdots \infty}


{:\implies \quad \sf f^(\prime \prime)(x)=2a_(2)+6a_(3)x+12a_(4)x^(2)+\cdots \cdots \infty}

Now , putting x = 0 will yield ;


{:\implies \quad \sf f^(\prime \prime)(0)=2a_(2)+6a_(3)(0)+12a_(4)(0)^(2)+\cdots \cdots \infty}


{:\implies \quad \sf f^(\prime \prime)(0)=2a_(2)}


{\boxed{:\implies \quad \sf a_(2)=(f^(\prime \prime)(0))/(2!)}}

Now , similarly we can prove that ;


{\boxed{:\implies \quad \sf a_(n)=(f^(n)(0))/(n!)}}

Now , as we had considered ;


{:\implies \quad \sf f(x)=a_(0)+a_(1)x+a_(2)x^(2)+a_(3)x^(3)+a_(4)x^(4)+\cdots \cdots \infty}

Now , putting the values we obtained above ;


{:\implies \quad \sf f(x)=f(0)+(x)/(1!)f^(\prime)(0)+(x^2)/(2!)f^(\prime \prime)(0)+(x^3)/(3!)f^(\prime \prime \prime)(0)+(x^4)/(4!)f^(\prime \prime \prime \prime)(0)+\cdots \cdots (x^n)/(n!)f^(n)(0)+\cdots \cdots \infty}

Hence , Proved

User Lorine
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