Question

a metal weighing 50.0g absorbs 20.0j of heat when its temperature increases by 150.0°c . what is the specific heat of the metal

Answer 1

2.677 J/g°C

Step-by-step explanation:

Quantity of heat required to raise the temperature of the metal,

Q = mc∆T

where m is the mass of the metal, c is the metal's specific heat capacity, and ∆T is the change in temperature that accompanies the heat transfer process

20.0J = 50.0g × c × 150°C

c = 20.0J/(50.0g × 150°C)

c = 2.677 J/g°C