Question

Put 3x+12y=-96 into slope intercept form

Answer 1

QUESTION:-

put 3x+12y=-96 into slope intercept form

SOLUTION:-

As we know that,

The slope intercept form:
`\pmb{y=mx+c }`

where,

• m=slope
• c=y-intercept

so,

• 
  `\pmb{3x+12y=-96 }`

• 
  `\pmb{12y=-3x-96 }`

• 
  `\pmb{y=(-3x-96)/(12) }`

• 
  `\pmb{y=(-3x)/(12)-(96)/(12) }`

• 
  `\pmb{y=-(1)/(4)x-8 }`

Answer 2

y =-1/4x -8

Explanation:

3x+12y=-96

Slope intercept form is y = mx +b where m is the slope and b is the y intercept

Subtract 3x from each side

3x -3x+12y=-3x-96

12y = -3x-96

Divide each side by 12

12y/12 = -3x/12 -96/12

y =-1/4x -8