Question

A biker starts from rest and reaches a speed of 10 m/s after t travelling with

uniform acceleration for 5 s. What is his acceleration?

Answer 1

`v = u + at \\ v = 10 \: m. {s}^( - 1) \\ u = 0 \\ t = 5 \: s \\ a = (v - u)/(t) \\ = (10 - 0)/(5) = (10)/(5) \\ \therefore \: a = 2 \: m. {s}^( - 2)`

Answer 2

2m/s^2

Step-by-step explanation:

we can use this formula to get the answer:

(vf - vi) / t = a

Since vf= 10m/s, vi=0m/s, and t=5

We can just substitute the values into the formula to get the result

that is:

(10 - 0) / 5 = 2m/s^2