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Let h(t) =-161+ 5t + 1. What is h(1)?
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Let h(t) =-161+ 5t + 1. What is h(1)?

User Erayerdem
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1 Answer

5 votes

Answer:

It is putting 1 at the place of t

so h(1)=161+5×1+1

h(1)=167

User Ken Zhang
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