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Tìm x : 2x^2-7x+3=0
giúp tui zới, please

User CHao
by
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1 Answer

5 votes

Solving Quadratic Equations with the Quadratic Formula

Answer:


x = 3 and
x = (1)/(2)\\

Step-by-step Explanation:

Recall:

if we have a quadratic equation,
ax^2 +bx +c = 0, where
a,
b and
c are real numbers and
a \\eq 0,
x = (-b \pm √(b^2 -4ac))/(2a).

Given:


2x^2 -7x +3 = 0

Solving for
x:


x = (-(-7) \pm √((-7)^2 -4(2)(3)))/(2(2)) \\ x = (-(-7) \pm √(49 -4(2)(3)))/(2(2)) \\ x = (7 \pm √(49 -24))/(4) \\ x = (7 \pm √(25))/(4) \\ x = (7 \pm 5)/(4)

Solving with the positive value:


x = (7 +5)/(4) \\ x = (12)/(4) \\ x = 3

Solving with the negative value:


x = (7 -5)/(4) \\ x = (2)/(4) \\ x = (1)/(2)

User Johan Classon
by
8.9k points

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