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Write an equation of a line that passes through point (5, 3) and is perpendicular to the line 2y = 5x – 8.

User Elric
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5 votes

Answer:

y= -2/5+5

Explanation:

A line must always be written in the form y= and the line given is not. Dividing both sides of the equation by 2 you get y=5/2x-4. This is the equation of the line given.

Perpendicular line have gradients that, when they are multiplied, they are equal to -1

The line given multiplied by the gradient of the line(the one required to find)= - 1. That is 5/2×line= -1.

Dividing both sides of the equation by 5/2 you'll get - 2/5. This is the gradient of the line required.

Using the general formula y=mx+c substitute the gradient into the equation. You'll get something like this y= -2/5x+c.

Substitute the given point into the equation. You'll get something like this 3= -2/5(5)+c.

Calculate the value of c. You'll get c=5.

Substitute the value of c into the original equation. You'll get something like this y= -2/5+5

This is the equation: y= -2/5+5

User Jignesh Panchal
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