Question

B. Write an exponential equation for the following situation. The drug dosage is 500 mg. The drug is

eliminated at a rate of 5.2% per hour. Use D = the amount of the drug in milligrams and t = time in
hours.
What is the equation for this?

Answer 1

General equation

• y=ab^x

Where

a is initial amount

b is rate of change

Here b=1-0.052=0.948

So equation

• D=500(0.948)^t

Answer 2

• D(t) = 500(0.948)^t

Explanation:

Initial amount = 500 mg

Elimination rate = 5.2% = 0.052 times per hour

This is the exponential decay and the equation would be:

• D(t) = 500*(1 - 0.052)^t ⇒ D(t) = 500(0.948)^t