Question

Evaluate the function at the given values.

h(x) = x² – 3x + 2
a. h(2)
b. h(-2)
c. h(0)
a. h(2)=

Answer 1

h(2) =0

h(-2) =4

h(0) = 2

h(2) = 0

Explanation:

h(2) = 2^2-3(2)+2 =4 - 6 + 2 = 0

h(-2) = 2^-2 -3(-2) +2 = -4+ 6+2=4

h(0) =0^2 - 3(0)+2 = 0-0 +2 = 2

h(2) = 2^2-3(2)+2 =4 - 6 + 2 = 0