Answer: Choice B
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Step-by-step explanation:
The endpoint (-7,-5) reflects over the line y = x when forming the inverse. It will reflect to (-5,-7). The x and y coordinates swap.
The new point (-5,-7) forms the vertex of a piece of a parabola. Since it's the vertex, we have something of the form y = a(x+5)^2 - 7 which matches with choices B and D.
However, we can rule out choice D because the interval is not x < -3. Try out a point like x = -100 and it will make x < -3 true, but -100 is definitely not part of the reflected parabola formed. Instead, we must have -5 < x < -3 as the domain of the inverse.
Notice how the range of the square root portion on the left is -5 < y < -3. The range of the original function forms the domain of the inverse, and vice versa. Effectively, all we're doing is replacing y with x when going from -5 < y < -3 to -5 < x < -3.
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Also another reason we can rule out choice D is to see that something like x = -2.5 will make log(x+2) to result in a non-real number. This is due to the fact that the domain of log(x) is x > 0. So the domain of log(x+2) is x > -2.