130k views
5 votes
Diagonals of Parallelograms

Find the length of VZ

Diagonals of Parallelograms Find the length of VZ-example-1

2 Answers

6 votes

Answer:

VZ = XV = 5(10) -8 = 50-8 = 42

VZ = 42

2x+ 10 = 5x-6

2x-5x + 10 = 5x-5x -6

-3x + 10 = -6

-3x + 10 + 6 = -6 +6

-3x + 16 = 0

x = 16/3

x = 5 1/3

5x -6 = 5 (5 1/3) -6

5x - 6 = 26 2/3 - 6

5x - 6 = 20 1/3

2x+10 = 3x

2x-3x +10 = 3x-3x

-x + 10 = 0

x = 10/1

x = 10

5x -1 = 5(10 ) - 8

5x -1 = 50 -8

5x-1 = 42 is true

User Kevin DiTraglia
by
4.7k points
1 vote

Answer:

YV = VW


2x + 10 = 3x \\ 3x - 2x = 10 \\ { \underline{ \: \: x = 10 \: \: }}


VZ = 5x - 8 \\ VZ = 5(10) - 8 \\ VZ = 50 - 8 \\ \\ { \underline{ \underline{ \: \: VZ = 42 \: \: }}}

User Grandouassou
by
4.2k points