#1
Here the basic reaction of C and O_2 occurs hence
![\\ \sf\bull\longmapsto {C\atop 1mol}+{O_2\atop 1mol}={CO_2\atop 2mol}](https://img.qammunity.org/2022/formulas/chemistry/high-school/hbbvwuun8bcp27auddyd25gxl5dey61fz3.png)
#2
First we have to find moles if Oxygen
- Mass=16g.
- Molar mass=16g/mol
![\\ \sf\bull\longmapsto No\:of\:moles=(Given\:mass)/(molar\:mass)](https://img.qammunity.org/2022/formulas/chemistry/high-school/wdxljhkmws0uqvzhlkp5qegpoybt3v58z1.png)
![\\ \sf\bull\longmapsto (16)/(16)](https://img.qammunity.org/2022/formulas/chemistry/high-school/48rsr7fxp9ochdggjzc0dtka8uyxleeta2.png)
![\\ \sf\bull\longmapsto 1mol](https://img.qammunity.org/2022/formulas/chemistry/high-school/rbrcwg8uqdn6znrfjw78b9oxw3qqplnl7l.png)
Hence
It will be same like 1st one i. e 2mols of CO_2 will be produced .
#3
Now we already found moles in 16g of dioxygen
Hence
![\\ \sf\bull\longmapsto {C\atop 2mol}+{O_2\atop 1mol}\longrightarrow {CO_2\atop 3mol}](https://img.qammunity.org/2022/formulas/chemistry/high-school/rmf8j20bxg9r4ctdxib3qiyyluy7xpyq0f.png)