Question

May someone help me solve d and e.

Answer 1

d.

`x = 2 {y}^(2) - 4 \\ 2 {y}^(2) = x + 4 \\ \\ {y}^(2) = (x + 4)/(2) \\ \\ y = \frac{ + }{} \sqrt{ (x + 4)/(2) } \\ \\ y = \frac{ + }{} ( √(x + 4) )/( √(2) ) * ( √(2) )/( √(2) ) \\ \\ y = \frac{ + }{} \: ( √(x + 4) * √(2) )/( √(2) √(2) ) \\ \\ y = \frac{ + }{} ( √(2(x + 4)) )/(2) \\ \\ y =( √(2(x + 4)) )/(2) \\ \\ y = - ( √(2(x + 4)) )/(2)`

e.

`x = {(y - 5)}^(2)`

with the root of both sides

`√(x) = \sqrt{ {(y - 5)}^(2) } \\ \\ \frac{ + }{} √(x) = y - 5 \\ \\ y = √(x) + 5 \\ y = - √(x) + 5`

I hope I helped you^_^