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2 votes
Find the slope of any line perpendicular to the line through ( – 6, 4) and (0,2).
25 POINTS

2 Answers

4 votes
  • (-6,4)
  • (0,2)


\\ \bull\tt\dashrightarrow Slope=(y_2-y_1)/(x_2-x_1)


\\ \bull\tt\dashrightarrow Slope=(2-4)/(0+6)


\\ \bull\tt\dashrightarrow Slope=(-2)/(6)


\\ \bull\tt\dashrightarrow Slope=(-1)/(3)

User Jochem
by
4.6k points
1 vote

Answer:

  • 3

Explanation:

Line through ( – 6, 4) and (0,2) has a slope:

  • m₁ = (2 - 4)/(0 - (-6)) = -2/6 = -1/3

The line perpendicular to this has a slope, negative-reciprocal to this:

  • m₂ = -1/m₁ = -1 /(-1/3) = 3
User Xipooo
by
4.3k points