16.1k views
2 votes
Find the slope of any line perpendicular to the line through ( – 6, 4) and (0,2).
25 POINTS

2 Answers

4 votes
  • (-6,4)
  • (0,2)


\\ \bull\tt\dashrightarrow Slope=(y_2-y_1)/(x_2-x_1)


\\ \bull\tt\dashrightarrow Slope=(2-4)/(0+6)


\\ \bull\tt\dashrightarrow Slope=(-2)/(6)


\\ \bull\tt\dashrightarrow Slope=(-1)/(3)

User Jochem
by
8.2k points
1 vote

Answer:

  • 3

Explanation:

Line through ( – 6, 4) and (0,2) has a slope:

  • m₁ = (2 - 4)/(0 - (-6)) = -2/6 = -1/3

The line perpendicular to this has a slope, negative-reciprocal to this:

  • m₂ = -1/m₁ = -1 /(-1/3) = 3
User Xipooo
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories