Question

B)

3. A car is travelling at initial speed u = 32 m/s. It then starts to decelerate with a = -2.0 m/s2
for 8.0 seconds.
a) What is the speed of the car after 8.0 seconds?
b) How far did the car travel during those 8.0 seconds?

Answer 1

a) 16m/s b) 192m

Step-by-step explanation:

v1=32m/s a=-2m/s^2 t=8s v2=? d=??

a) I will use this equation v2= v1 + a*t

v2= 32m/s + -2m/s^2 * 8s

v2= 32m/s + -16m/s

v2= 16m/s

b) v2^2=v1^2 + 2ad

rearranging

v2^2-v1^2=2ad

v2^2-v1^2/2= a d

v2^2-v1^2/2a=d

16m/s^2 - 32m/s^2/ 2 x-2m/s^2 =d

d=192m