Answer:
12 free throws
10 2-pointers
4 3-pointers
Explanation:
Let x = 1 point
y = 2 point
z = 3 point
x + y + z = 26
x = y + 2
x = 3z
Let's make it to where the last two equations are in terms of x
Subtract 2 from both sides of the middle equation
x = y + 2
- 2 - 2
y = x - 2
Divide both sides by 3 in the bottom equation
x/3 = 3z/3
z = x/3
Now plug in the new y and z
x + x - 2 + x/3 = 26
2x + x/3 - 2 = 26
Add 2 to both sides
2x + x/3 - 2 = 26
+ 2 + 2
2x + x/3 = 28
Add up the x terms and don't forget about common denominators
6x/3 + x/3 = 28
7/3x = 28
Multiply both sides by 3/7 to isolate the x variable
(7/3x = 28)3/7
x = 12
Now plug the new x into the original equations to find the remaining variables.
12 = y + 2
- 2 - 2
y = 10
12 = 3z
12/3 = 3z/3
z = 4