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F(x)=x^3+4x^2+3x intervals
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F(x)=x^3+4x^2+3x intervals

User KakhkAtion
by
5.4k points

1 Answer

3 votes

Answer:

Increasing on: (−∞,−3),(13,∞)

Decreasing on: (−3,13)

f(x)=x3+4x2−3x−18

Explanation:

I'm not fully sure though

User Ravishi
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