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an 8in by 12in picture has a frame of uniform width around it the area of the frame is equal to the area of the picture. what is the width of the frame

User Jordan D
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1 Answer

5 votes

Answer:

2 inches

Explanation:

The area of the frame will be the difference between the area of the picture with frame, and the area of the picture without. We want that difference to be equal to the area of the picture without the frame.

Let x represent the width of the frame. The overall length and width of the picture will be increased by 2x when the frame is added. Then we have ...

a = LW = (8+2x)(12+2x) . . . . area of picture and frame

b = LW = (8)(12) . . . . . . . . . . area of picture

a -b = b . . . . . . desired relationship between areas

Substituting and expanding the expressions for 'a' and 'b', we find ...

a -2b = 0 . . . . subtract b

(8 +2x)(12 +2x) -2(8)(12) = 0

4x² +40x -96 = 0 . . . simplify

x² +10x -24 = 0 . . . . . divide by 4

(x -2)(x +12) = 0 . . . . factor

The positive value of x that makes this true is x = 2.

The width of the frame is 2 inches.

User Alessandra Pereyra
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