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If f(x)= x2 – 3, then f(a-b) in standard
form is equivalent to:

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\huge \bf༆ Answer ༄

We have to find : f (a - b) = ?


{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:f(x) = {x}^(2) - 3


{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:f(a - b) = (a - b) {}^(2) - 3


{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:f(a - b) = {a}^(2) + {b}^(2) - 2ab - 3

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