Question

Find


`y = \sqrt{ (x + 7)/(x - 2) }`
a)

`x = 5`
b)

`y = 4`
​

Answer 1

Explanation:

`y = \sqrt{ (x + 7)/(x - 2) } \\ case1)x = 5 \\ y = \sqrt{ (5 + 7)/(5 - 2) } = \sqrt{ (12)/(3) } = √(4) = 2 \\ y = 2 \\ case2) \: y = 4 \\ 4 = \sqrt{ (x + 7)/(x - 2) } \\ squaring \: both \: side \\ {4}^(2) = { (\sqrt{ (x + 7)/(x - 2) } )}^(2) \\ 16 = ( x + 7)/(x - 2) \\ 16(x - 2) = x + 7 \\ 16x - 32 = x + 7 \\ 16x - x = 7 + 32\\ 15x = 39 \\ x = (39)/(15) = 2.6`