Question

Please help me

Calculate the percentage of nitrogen in the two important nitrogen fertilizers,ammonia, NH3 and Urea, CO(NH2)2

Answer 1

Percent composition = mass of element in the compound/mass of compound × 100

In this case, the mass of the compound is its molar mass.

Percent Composition of N in CO(NH2)2 (urea)

Molar mass CO(NH2)2 = 60.056 g/mol

Mass of N = 2×14.007 g/mol = 28.014 g/mol

%N: 28.014 g/mol/60.056 g/mol × 100 = 46.646%

Percent Composition of N in NH4NO3 (ammonium nitrate)

Molar mass of NH4NO3 = 80.044g/mol

Mass of N = 2×14.007 = 28.014 g/mol

%N: 28.014 g/mol/80.044 g/mol × 100 = 34.998%

Hope this helps, please let me know If I'm wrong.