Question

Write an equation of the line perpendicular to

the given line that contains point D.
D(6, 2); y = -3x + 5

Answer 1

From general equation of a line:

`y = mx + b`

m » slope, b » y-intercept.

but perpendicularly:

`m _(1) * m _(2) = - 1 \\ - 3 * m = - 1 \\ m = (1)/(3)`

at point (6, 2):

`2 = ( (1)/(3) * 6) + b \\ 2 = 2 + b \\ b = 0`

therefore, equation is :

`{ \boxed{ \boxed{y = (1)/(3) x}}}`