Question

Sin30. cot45/cos30. tan60​

Answer 1

`( \sin(30) \cot(45) )/( \cos(30) \tan(60) ) \\`

group them by simplifying:

`= \{ ( \sin(30) )/( \cos(30) ) . ( \cot(45) )/( \tan(60) ) \} \\ \\ = ( \tan(30) )/( \tan(45) \tan(60) ) \\ \\ = (( (1)/( √(3) )) )/(1 * √(3) ) \\ \\ = (1)/( √(3) ) * (1)/( √(3) ) \\ \\ = \frac{1}{ {( √(3)) }^(2) } \\ \\ = { \boxed{ \boxed{ (1)/(3) }}}`