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The smallest of three consecutive integers is added to four times the largest integer; the result so obtained is 15 less than three times the middle integer. Find the integers. ​

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Answer:

Let the three consecutive integers be x,x+1,x+2

ATQ

x+2(x+2)+15=4(x+1)

=3x+19=4x+4

= x=15

..... Hence. The nos. Are 15,15+1=16 and 15+2=17

Explanation:

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