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Find an equation for the perpendicular bisector of the line segment whose endpoints are (-1,6) and (7,2).

User Sepehrom
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1 Answer

5 votes

Answer:


y=2x-2

Explanation:

First, lets find the mid-point between those two points:


((-1+7)/(2),(6+2)/(2))\\=(3,4)

Now, lets find the gradient of the perpendicular bisector:


-1*((6-2)/(-1-7))^(-1)\\=-1*(-8)/(4)\\=2

Next, we can find the equation:


y=2x+c\\4=2*3+c\\c=4-6\\c=-2\\\Rightarrow y=2x-2

User Nilesh Wagh
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3.8k points