Question

`211=6(3+8x)+1`

Answer 1

X=4
211=18+48x+1
211=19+48x

Answer 2

Rearrange terms

`⟹ 211 = 6(3 + 8x) + 1 \: \\ ⟹211 = 6(8x + 3) + 1`

Add the numbers

`⟹ 211 = 48x + 19`

Subtract 19 from both sides of the equation

`⟹211 = 48x + 19 - 19`

Subtract the numbers

`⟹ \: 192 = 48x + 19 - 19`

`⟹\: 192 = 48x`

Divide both sides of the equation by the same term

Divide the numbers

`\\ ⟹ (192)/(48x) = (48x)/(48) \\ \: ⟹ \: \: \: \: \: \: \: 4 = (48x)/(48)`

Cancel terms that are in both the numerator and denominator

`\\ \: ⟹\: 4 = (48x)/(48)`

Move the variable to the left

`\\ ⟹4 = x`

`\\ ⟹x = 4`

`⇒ \: Ans \: ⇒ x = 4 \: ⇐`