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A rectangle with an area of 32in^2 has one side measuring 4in. A similar rectangle has an area of 288in^2. How long is the longer side in the larger rectangle?

User Revgum
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First find length of smaller rectangle


\\ \sf\longmapsto L4=32


\\ \sf\longmapsto L=32/4=8in

Now the ration will be same


\\ \sf\longmapsto (32)/(8)=(288)/(x)


\\ \sf\longmapsto 4x=288


\\ \sf\longmapsto x=(288)/(4)


\\ \sf\longmapsto 72in

The longer side of larger rectangle measures 72in

User Garret
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