Answer:
Corrected Question:
[ Refer to the above attachment ]
Solution:
In the given figure there are two shapes:
- A Rectangle
- A Triangle
First, we have to find the area of Rectangle ABGF & DCGE. After that, area of triangle CHB.
1) Area of Rectangle ABGF:
As, we know:
Formula for Area :-
★ Length × Breadth ★
where,
- Length = FA = 4cm
- Breadth = GF = 10cm ( 7+3 )
➝ 4 cm × 10 cm
➝ 40 cm²
Hence, the area of Rectangle ABGF is 40cm².
2) Area of Rectangle DCGE:
As, we know:
Formula for Area :-
★ Length × Breadth ★
where,
- Length = ED = 4cm
- Breadth = DC = 7cm
➝ 4 cm × 7 cm
➝ 28 cm²
Hence, the area of Rectangle DCGE is 28cm².
3) Area of Triangle CHB:
As, we know:
Formula for Area :-
★ ½ ( base × height ) ★
where,
➝ ½ ( 3cm × 8cm )
➝ ½ ( 24cm )
➝ ½ × 24cm
➝ 12 cm²
Hence the Area of Triangle CHB is 12cm².
Now, Area of Given Shape is:
➝ 40cm² + 28cm² + 12cm²
➝ 52cm² + 28cm²
➝ 80cm²
Thus, the area of the given shape is 80cm².
____________________
Additional Information:
[ Formula's for Area ]
★ Square = (Side)²
★ Rectangle = Length × Breadth
★ Triangle = ½bh
★ Circle = πr²