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What is the equation of the line that passes through the point (-6, 1) and has a
slope of 1/6?

2 Answers

2 votes

Answer:

y=1/6x+2

Explanation:

y-y1=m(x-x1)

y-1=1/6(x-(-6))

y-1=1/6(x+6)

y=1/6x+6/6+1

y=1/6x+1+1

y=1/6x+2

User Majster
by
3.6k points
3 votes

Answer:

y=1/6x+2

Explanation:

Hi there!

We want to find the equation of the line that passes through (-6, 1) and has a slope of 1/6

The typical way to write the equation of the line is y=mx+b, where m is the slope, and b is the y intercept

As we are already given the slope (1/6), we can immediately substitute that into the equation:

y=1/6x+b

Now we need to find b

As the equation of the line passes through (-6, 1), we can substitute its values into the equation to solve for b

Substitute the value of x as -6 and the value of y as 1

1=1/6(-6)+b

Multiply

1=-1+b

Add 1 to both sides

2=b

Substitute 2 as b

y=1/6x+2

Hope this helps!