Answer:
Cos A = 1.01
Sin A = 8.06
Cosec A = 0.1241
Sec A = 0.9926
Tan A = 1/8 = 0.1250
Explanation:
cot A = 1/tan A.
if Cot A = 8 and cot A = 1/tanA
then,
8= 1/tan A
by cross multiplying
8tan A = 1
dividing both sides by 8
tan A = 1/8
recall SOH CAH TOA
tangent = opposite/adjacent
therefore, given a right angle triangle with adjacent= 8 and opposite = 1 therefor hypotenuse will be according to pythagora's theorem,
hypotenuse^2 = opposite^2 + adjacent^2
let hypotenuse be h, opposite be o and adjacent be a
h^2 = o^2 + a^2
h^2 = 1^2 + 8^2
h^2 = 1 + 64
h^2 = 65
taking square roots of both sides we have
h = 8.06 to 2 decimal places.
sin A = opposite/ hypotenuse
Sin A = 1/8.06
Sin A = 0.1241
Cos A = adjacent/ hypotenuse
Cos A = 8/8.06
Cos A = 0.9926 to 4 significant figures
Cosec A = 1/Sin A
Cosec A = 1/0.1241
Cosec A = 8.06
Sec A = 1/Cos A
Sec A = 1/0.9926
Sec A = 1.01 to 2 decimal places.