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10 votes
10 votes
Find all real solutions Tan pi/3 x-3=0

User Petter Brodin
by
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1 Answer

16 votes
16 votes

Explanation:

If the question is like this,


\tan( (\pi)/(3)x - 3 ) = 0

We take the arc tan of both sides.


\tan( - 1) ( \tan( (\pi)/(3)x - 3 ) = \tan {}^( - 1) ( {}^( )0 )


(\pi)/(3) x - 3 = 0


(\pi)/(3) x = 3


= (9)/(\pi)

Since the period of a tan function, is pi, we divide pi by pi/3 since pi/3is the coeffeicent of the x variable


(\pi)/( (\pi)/(3) ) = 3

So the answer is


(9)/(\pi) + 3n

If this the question,


\tan( (\pi)/(3) x) = 3


(\pi)/(3) x = 1.249


x = (3.747)/(\pi)

The period is once again 3 so we have


(3.747)/(\pi) + 3n

where n is a interger.

User Muhammedv
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2.6k points